e.g. a plane flies 100km from point A on a bearing of 060 degrees to point B then it changes it's direction on a bearing of 195 degrees and flies fro 120km to point C what is the distance and bearing between points A and CCan someone explain how to work out bearings with distances?
The problem is solved using Trigonometry and Pythagoras. First draw a rough triangle and drop a perpendicular from the position A which should be at the top. work out the distance from the position B to the position where the perpendicular cuts the base (B-C) and the height from base to position A. The distance from A to C is then worked out by applying Pythagoras to the distance the position where the vertical cuts the base to the height and you have the distance from A to C.Can someone explain how to work out bearings with distances?
You can use Law of Cosines and Law of Sines for this solution, but breaking the vectors into components may be more comfortable:
100 @ 60掳 = 50鈭? @ 0掳 + 50 @ 90掳
120 @ 195掳 鈮?- 115.91 @ 0掳 -31.058 @ 90掳
AC = 29.307 @ 180掳 + 18.942 @ 90掳
AC = 34.896 km @ 122.88掳
http://www.theingots.org/community/node/鈥?/a>
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